Optimal. Leaf size=181 \[ -\frac{16 x^3 \sqrt{a+i a \sinh (e+f x)}}{f^2}+\frac{96 x^2 \tanh \left (\frac{e}{2}+\frac{f x}{2}+\frac{i \pi }{4}\right ) \sqrt{a+i a \sinh (e+f x)}}{f^3}-\frac{384 x \sqrt{a+i a \sinh (e+f x)}}{f^4}+\frac{768 \tanh \left (\frac{e}{2}+\frac{f x}{2}+\frac{i \pi }{4}\right ) \sqrt{a+i a \sinh (e+f x)}}{f^5}+\frac{2 x^4 \tanh \left (\frac{e}{2}+\frac{f x}{2}+\frac{i \pi }{4}\right ) \sqrt{a+i a \sinh (e+f x)}}{f} \]
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Rubi [A] time = 0.212391, antiderivative size = 181, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 3, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.143, Rules used = {3319, 3296, 2638} \[ -\frac{16 x^3 \sqrt{a+i a \sinh (e+f x)}}{f^2}+\frac{96 x^2 \tanh \left (\frac{e}{2}+\frac{f x}{2}+\frac{i \pi }{4}\right ) \sqrt{a+i a \sinh (e+f x)}}{f^3}-\frac{384 x \sqrt{a+i a \sinh (e+f x)}}{f^4}+\frac{768 \tanh \left (\frac{e}{2}+\frac{f x}{2}+\frac{i \pi }{4}\right ) \sqrt{a+i a \sinh (e+f x)}}{f^5}+\frac{2 x^4 \tanh \left (\frac{e}{2}+\frac{f x}{2}+\frac{i \pi }{4}\right ) \sqrt{a+i a \sinh (e+f x)}}{f} \]
Antiderivative was successfully verified.
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Rule 3319
Rule 3296
Rule 2638
Rubi steps
\begin{align*} \int x^4 \sqrt{a+i a \sinh (e+f x)} \, dx &=\left (\text{csch}\left (\frac{e}{2}-\frac{i \pi }{4}+\frac{f x}{2}\right ) \sqrt{a+i a \sinh (e+f x)}\right ) \int x^4 \sinh \left (\frac{e}{2}-\frac{i \pi }{4}+\frac{f x}{2}\right ) \, dx\\ &=\frac{2 x^4 \sqrt{a+i a \sinh (e+f x)} \tanh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right )}{f}-\frac{\left (8 \text{csch}\left (\frac{e}{2}-\frac{i \pi }{4}+\frac{f x}{2}\right ) \sqrt{a+i a \sinh (e+f x)}\right ) \int x^3 \cosh \left (\frac{e}{2}-\frac{i \pi }{4}+\frac{f x}{2}\right ) \, dx}{f}\\ &=-\frac{16 x^3 \sqrt{a+i a \sinh (e+f x)}}{f^2}+\frac{2 x^4 \sqrt{a+i a \sinh (e+f x)} \tanh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right )}{f}-\frac{\left (48 i \text{csch}\left (\frac{e}{2}-\frac{i \pi }{4}+\frac{f x}{2}\right ) \sqrt{a+i a \sinh (e+f x)}\right ) \int x^2 \cosh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right ) \, dx}{f^2}\\ &=-\frac{16 x^3 \sqrt{a+i a \sinh (e+f x)}}{f^2}+\frac{96 x^2 \sqrt{a+i a \sinh (e+f x)} \tanh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right )}{f^3}+\frac{2 x^4 \sqrt{a+i a \sinh (e+f x)} \tanh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right )}{f}-\frac{\left (192 \text{csch}\left (\frac{e}{2}-\frac{i \pi }{4}+\frac{f x}{2}\right ) \sqrt{a+i a \sinh (e+f x)}\right ) \int x \cosh \left (\frac{e}{2}-\frac{i \pi }{4}+\frac{f x}{2}\right ) \, dx}{f^3}\\ &=-\frac{384 x \sqrt{a+i a \sinh (e+f x)}}{f^4}-\frac{16 x^3 \sqrt{a+i a \sinh (e+f x)}}{f^2}+\frac{96 x^2 \sqrt{a+i a \sinh (e+f x)} \tanh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right )}{f^3}+\frac{2 x^4 \sqrt{a+i a \sinh (e+f x)} \tanh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right )}{f}-\frac{\left (384 i \text{csch}\left (\frac{e}{2}-\frac{i \pi }{4}+\frac{f x}{2}\right ) \sqrt{a+i a \sinh (e+f x)}\right ) \int \cosh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right ) \, dx}{f^4}\\ &=-\frac{384 x \sqrt{a+i a \sinh (e+f x)}}{f^4}-\frac{16 x^3 \sqrt{a+i a \sinh (e+f x)}}{f^2}+\frac{768 \sqrt{a+i a \sinh (e+f x)} \tanh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right )}{f^5}+\frac{96 x^2 \sqrt{a+i a \sinh (e+f x)} \tanh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right )}{f^3}+\frac{2 x^4 \sqrt{a+i a \sinh (e+f x)} \tanh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right )}{f}\\ \end{align*}
Mathematica [A] time = 0.23611, size = 141, normalized size = 0.78 \[ \frac{2 \sqrt{a+i a \sinh (e+f x)} \left (\left (f^4 x^4-8 i f^3 x^3+48 f^2 x^2-192 i f x+384\right ) \sinh \left (\frac{1}{2} (e+f x)\right )+i \left (f^4 x^4+8 i f^3 x^3+48 f^2 x^2+192 i f x+384\right ) \cosh \left (\frac{1}{2} (e+f x)\right )\right )}{f^5 \left (\cosh \left (\frac{1}{2} (e+f x)\right )+i \sinh \left (\frac{1}{2} (e+f x)\right )\right )} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.087, size = 174, normalized size = 1. \begin{align*}{\frac{i\sqrt{2} \left ( i{x}^{4}{f}^{4}+{f}^{4}{x}^{4}{{\rm e}^{fx+e}}+8\,i{x}^{3}{f}^{3}-8\,{f}^{3}{x}^{3}{{\rm e}^{fx+e}}+48\,i{x}^{2}{f}^{2}+48\,{f}^{2}{x}^{2}{{\rm e}^{fx+e}}+192\,ixf-192\,fx{{\rm e}^{fx+e}}+384\,i+384\,{{\rm e}^{fx+e}} \right ) \left ({{\rm e}^{fx+e}}-i \right ) }{ \left ( i{{\rm e}^{2\,fx+2\,e}}-i+2\,{{\rm e}^{fx+e}} \right ){f}^{5}}\sqrt{a \left ( i{{\rm e}^{2\,fx+2\,e}}-i+2\,{{\rm e}^{fx+e}} \right ){{\rm e}^{-fx-e}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{i \, a \sinh \left (f x + e\right ) + a} x^{4}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: UnboundLocalError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int x^{4} \sqrt{a \left (i \sinh{\left (e + f x \right )} + 1\right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{i \, a \sinh \left (f x + e\right ) + a} x^{4}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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